F(-2)=4x^2+5x+3

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Solution for F(-2)=4x^2+5x+3 equation: 



(-2)=4F^2+5F+3

We move all terms to the left:

(-2)-(4F^2+5F+3)=0

We add all the numbers together, and all the variables

-(4F^2+5F+3)-2=0

We get rid of parentheses

-4F^2-5F-3-2=0

We add all the numbers together, and all the variables

-4F^2-5F-5=0

a = -4; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·(-4)·(-5)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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